Statistics (Ex – 15.1)
Find the mean deviation about the mean for the data in Exercises 1 and 2.
Question 1.
4, 7, 8, 9, 10, 12, 13, 17
Solution:
Mean of the given data is
Question 2.
38, 70, 48, 40, 42, 55, 63, 46, 54, 44
Solution:
Mean of the given data is
Question 3.
13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17
Solution:
Arranging the data in ascending order, we have
10, 11, 11, 12, 13, 13, 14, 16, 16, 17, 17, 18
Here n = 12 (which is even)
So median is the average of 6th and 7th observations
Question 4.
36, 72, 46, 42, 60, 45, 53, 46, 51, 49
Solution:
Arranging the data in ascending order, we have 36, 42, 45, 46, 46, 49, 51, 53, 60, 72
Here n = 10 (which is even)
So median is the average of 5th and 6th observations
Find the mean deviation about the mean for the data in Exercises 5 and 6.
Question 5.
Solution:
Question 6.
Solution:
Find the mean deviation about the median for the data in Exercises 7 and 8.
Question 7.
Solution:
Question 8.
Solution:
Find the mean deviation about the mean for the data in Exercises 9 and 10.
Question 9.
Solution:
Question 10.
Solution:
Question 11.
Find the mean deviation about median for the following data:
Solution:
Question 12.
Calculate the mean deviation about median age for the age distribution of 100 persons given below:
[Hint: Convert the given data into continuous frequency distribution by subtracting 0.5 from lower limit and adding 0.5 to the upper limit of each class interval]
Solution: