Binomial Theorem (Ex – 8.2)
Question 1.
Find the coefficient of x5 in (x + 3)8
Solution.
Suppose x5 occurs in the (r + 1)th term of the expansion (x + 3)8

Question 2.
a5 b7in (a-2b)12
Solution.
Suppose a5 b7 occurs in the (r + 1)th term of the expansion (a – 2b)12.

Write the general term in the expansion of
Question 3.
(x2 – y)6
Solution.

Question 4.
(x2 – yx)12, x ≠ 0
Solution.
We have given, (x2 – yx)12 = (x2 + (- yx))12, x ≠ 0

Question 5.
Find the 4th term in the expansion of (x – 2y)12.
Solution.

Question 6.

Solution.

Find the middle terms in the expansions of
Question 7.

Solution.
As the exponent 7 is odd, so there will be two middle terms in the expansion

Question 8.

Solution.

Question 9.
In the expansion of (1 + a)m+n, prove that coefficients of am and an are equal.
Solution.

Question 10.
The coefficients of the (r – 1)th, rth and (r + 1)th terms in the expansion of (x + 1 )n are in the ratio 1: 3: 5. Find n and r.
Solution.

Question 11.
Prove that the coefficient of xn in the expansion of (1 + x)2n is twice the coefficient of xn in the expansion of (1 + x)2n-1.
Solution.

Question 12.
Find a positive value of m for which the coefficient of x2 in the expansion (1 + x)m is 6.
Solution.
