C.B.S.E Solution

Chapter 7 – Permutations and Combinations (Ex – 7.4)

Permutations and Combinations (Ex – 7.4) Question 1.If nC8 = nC2, find nC2. Solution.We have, nC8 = nC2 Question 2.Determine n if(i) 2nC3: nC3 =12 : 1(ii) 2nC3: nC3= 11 : 1 Solution. Question 3.How many chords can be drawn through 21 points on a circle? Solution. Question 4.In how many ways can a team of 3 boys and 3 girls be selected from 5 boys and […]

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Chapter 7 – Permutations and Combinations (Ex – 7.3)

Permutations and Combinations (Ex – 7.3) Question 1.How many 3-digit numbers can be formed by using the digits 1 to 9 if no digit is repeated? Solution.Total digits are 9. We have to form 3 digit numbers without repetition.∴ The required 3 digit numbers = 9P3=9!/6!=9×8×7×6!/6!=504 Question 2.How many 4-digit numbers are there with no digit

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Chapter 7 – Permutations and Combinations (Ex – 7.1)

Permutations and Combinations (Ex – 7.1) Question 1.How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that(i) repetition of the digits is allowed?(ii) repetition of the digits is not allowed? Solution.(i) (ii) When repetition is not allowed then first place can be filled in 5 different ways, second

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Chapter 6 – Linear Inequalities (Ex – 6.1)

Linear Inequalities (Ex – 6.1) Question 1.Solve 24x < 100, when(i) x is a natural number(ii) x is an integer. Solution. Question 2.Solve – 12x > 30, when(i) x is a natural number(ii) x is an integer Solution. The linear inequality solver she used can give test data that are not certain to produce the required path

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Chapter 5 – Complex Numbers and Quadratic Equations (Ex – 5.3)

Complex Numbers and Quadratic Equations (Ex – 5.3) Solve each of the following equations: Question 1.×2 + 3 = 0 Solution. Question 2.2×2 + x + 1 = 0 Solution.We have, 2×2 + x + 1 = 0Comparing the given equation with the general form ax2 + bx + c = 0, we get Question 3.×2 + 3x + 9

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Chapter 5 – Complex Numbers and Quadratic Equations (Ex – 5.2)

Complex Numbers and Quadratic Equations (Ex – 5.2) Find the modulus and the arguments of each of the complex numbers in Exercises 1 to 2. Question 1. Solution. Question 2. Solution.We have, Convert each of the complex numbers given in Exercises 3 to 8 in the polar form: Question 3.1 – i Solution.We have, z

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Chapter 5 – Complex Numbers and Quadratic Equations (Ex – 5.1)

Complex Numbers and Quadratic Equations (Ex – 5.1) Express each of the complex number given in the Exercises 1 to 10 in the form a + ib. Question 1.(5i)(−3/5i) Solution.(5i)(−3/5i)= -3i2 = -3(-1)                    [∵ i2 = -1]= 3 = 3 + 0i Question 2.i9+ i19 Solution. Question 3.i-39

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