Complex Numbers and Quadratic Equations (Ex – 5.2)
Find the modulus and the arguments of each of the complex numbers in Exercises 1 to 2.
Question 1.
Solution.
Question 2.
Solution.
We have,
Convert each of the complex numbers given in Exercises 3 to 8 in the polar form:
Question 3.
1 – i
Solution.
We have, z = 1 – i
Question 4.
-1 + i
Solution.
We have, z = -1 + i
Question 5.
-1 – i
Solution.
We have, z = -1 – i
Question 6.
-3
Solution.
We have, z = -3, i.e., z = -3 + 0i
Question 7.
Solution.
We have,
Question 8.
i
Solution.
We have, z = i, i.e., z = 0 + 1.i